struct AnyBitmapextension AnyBitmap : AutomationValue, Bitmap, Equatable, ExpressibleByArrayLiteral, Hashable, OptionSet, RawRepresentable, Sendable, SetAlgebraA type-erased Bitmap
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Creates a new option set from the given raw value.
This initializer always succeeds, even if the value passed as
rawValueexceeds the static properties declared as part of the option set. This example creates an instance ofShippingOptionswith a raw value beyond the highest element, with a bit mask that effectively contains all the declared static members.let extraOptions = ShippingOptions(rawValue: 255) print(extraOptions.isStrictSuperset(of: .all)) // Prints "true"Declaration
Swift
init(rawValue: UInt64)Parameters
rawValueThe raw value of the option set to create. Each bit of
rawValuepotentially represents an element of the option set, though raw values may include bits that are not defined as distinct values of theOptionSettype. -
The corresponding value of the raw type.
A new instance initialized with
rawValuewill be equivalent to this instance. For example:enum PaperSize: String { case A4, A5, Letter, Legal } let selectedSize = PaperSize.Letter print(selectedSize.rawValue) // Prints "Letter" print(selectedSize == PaperSize(rawValue: selectedSize.rawValue)!) // Prints "true"Declaration
Swift
var rawValue: UInt64 { get } -
Returns a Boolean value indicating whether two values are equal.
Equality is the inverse of inequality. For any values
aandb,a == bimplies thata != bisfalse.Declaration
Swift
static func == (lhs: AnyBitmap, rhs: AnyBitmap) -> BoolParameters
lhsA value to compare.
rhsAnother value to compare.
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Hashes the essential components of this value by feeding them into the given hasher.
Implement this method to conform to the
Hashableprotocol. The components used for hashing must be the same as the components compared in your type’s==operator implementation. Callhasher.combine(_:)with each of these components.Important
In your implementation of
hash(into:), don’t callfinalize()on thehasherinstance provided, or replace it with a different instance. Doing so may become a compile-time error in the future.Declaration
Swift
func hash(into hasher: inout Hasher)